Webcannot reshape array of size 136415664 into shape (2734 ... Since you have 136,415,664 values, the reshaping is impossible. If your fourth dimension is 4, then the reshape will be possible. WebFeb 16, 2024 · two_d_arr.reshape(4, -1) two_d_arr-----ValueError: cannot reshape array of size 6 into shape (4,newaxis) We have six values, so we can only reshape the array into the number of dimensions that can hold …

Using NumPy reshape() to Change the Shape of an Array

WebFeb 17, 2024 · Note that the v and M objects are both of the type ndarray that the numpy module provides. The difference between the v and M arrays is only their shapes. We can get information about the shape of an array by using the ndarray.shape property.. Since it is statically typing, we can explicitly define the type of the array data when we create it, … WebAug 13, 2024 · Stepping back a bit, you could have used test_image directly, and not needed to reshape it, except it was in a batch of size 1. A better way to deal with it, and … phone with headset

python - Cannot reshape array - Stack Overflow

WebOct 4, 2024 · 1 Answer. You need 2734 × 132 × 126 × 1 = 45, 471, 888 values in order to reshape into that tensor. Since you have 136, 415, 664 values, the reshaping is … WebDec 18, 2024 · So, if you don't want a ValueError, you need to reshape the input into a differently sized array where it fits correctly. Solution 2. the reshape has the following syntax. data.reshape(shape) shapes are passed in the form of tuples (a, b). so try, data.reshape((-1, 1, 28, 28)) Solution 3. Try like this WebMar 22, 2024 · According to your code, the initial shape of X is $(30, 100, 100, 3)$ which translates to having $30$ images each of $(100 \times 100)$ dimension and $3$ channels. To flatten X from $(30,100,100,3)$ to $(30, 100\times100\times3)$ you could replace: phone with hdmi on top